Bumped versions for ghc 7.10 and base 4.8.
{-# LANGUAGE BangPatterns #-}
module System.IO.Streams.Concurrent.Unagi
( -- * Channel conversions
inputToChan
, chanToInput
, chanToOutput
, makeChanPipe
, chanToPipe
, dupStream
) where
------------------------------------------------------------------------------
import Control.Applicative ((<$>), (<*>))
import Control.Concurrent.Chan.Unagi (InChan, OutChan, dupChan,
newChan, readChan, writeChan)
import Control.Monad ((>=>))
import Prelude hiding (read)
import System.IO.Streams.Internal (InputStream, OutputStream,
makeInputStream,
makeOutputStream, read)
------------------------------------------------------------------------------
-- | Writes the contents of an input stream to a channel until the input stream
-- yields end-of-stream.
inputToChan :: InputStream a -> InChan (Maybe a) -> IO ()
inputToChan is ch = go
where
go = do
mb <- read is
writeChan ch mb
maybe (return $! ()) (const go) mb
------------------------------------------------------------------------------
-- | Turns an 'OutChan' into an input stream.
--
chanToInput :: OutChan (Maybe a) -> IO (InputStream a)
chanToInput ch = makeInputStream $! readChan ch
------------------------------------------------------------------------------
-- | Turns an 'InChan' into an output stream.
--
chanToOutput :: InChan (Maybe a) -> IO (OutputStream a)
chanToOutput = makeOutputStream . writeChan
--------------------------------------------------------------------------------
-- | Create a new pair of streams using an underlying 'Chan'. Everything written
-- to the 'OutputStream' will appear as-is on the 'InputStream'.
--
-- Since reading from the 'InputStream' and writing to the 'OutputStream' are
-- blocking calls, be sure to do so in different threads.
makeChanPipe :: IO (InputStream a, OutputStream a)
makeChanPipe = do
(inChan, outChan) <- newChan
(,) <$> chanToInput outChan <*> chanToOutput inChan
--------------------------------------------------------------------------------
-- | Create a new pair of streams form the given 'Chan'. Everything written
-- to the 'OutputStream' will appear as-is on the 'InputStream'.
--
-- Since reading from the 'InputStream' and writing to the 'OutputStream' are
-- blocking calls, be sure to do so in different threads.
chanToPipe :: (InChan (Maybe a), OutChan (Maybe a)) -> IO (InputStream a, OutputStream a)
chanToPipe (inChan, outChan) = (,) <$> chanToInput outChan <*> chanToOutput inChan
--------------------------------------------------------------------------------
-- | Create a new input stream duplicated from the 'InChan'
--
dupStream :: InChan (Maybe a) -> IO (InputStream a)
dupStream = dupChan >=> chanToInput